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7 October, 16:44

What are the dimensions of a rectangular box with a volume of 50b3 - 3 - 2b + 75b2?

(2b + 3); (5b - 1); (5b - 1)

(2b + 3); (5b + 1); (5b - 1)

(2b - 3); (5b - 1); (5b + 1)

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  1. 7 October, 19:00
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    So the formula for getting the volume of a rectangular box is V = lxwxh.

    Given the volume above, the dimensions of the box would be: (2b + 3); (5b + 1); (5b - 1) So when you multiply these given dimensions, the result would be 50b3+75b2-2b-3. I hope that this is the answer that you are looking for.
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