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30 January, 20:47

Hank raises mealworms. in a square of compost 5 ft by 5 ft, he can have 2,000 mealworms. how many mealworms can he have if his square of compost has a side length that is six times longer?

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  1. 30 January, 23:03
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    The answer is 72,000 mealworms.

    Step 1. Calculate the number of mealworms per 1 square ft.

    The square of compost 5 ft by 5 ft, has the area: A = 5² = 25 ft²

    On 25 ft² there are 2,000 mealworms. On 1 ft² there are x mealworms.

    25 ft² : 2,000 mealworms = 1 ft² : x

    x = 2,000 mealworms * 1 ft² : 25 ft²

    x = 80 mealworms.

    Step 2. Calculate the area of the new square with side length that is six times longer.

    A = (5*6) ² = 30² = 900 ft²

    Step 3. Calculate the number of mealworms (x) on 900 ft², if there are 80 mealworms per 1 ft².

    x : 900 ft² = 80 mealworms : 1 ft²

    x = 80 mealworms : 1 ft² * 900 ft²

    x = 72,000 mealworms.
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