T (n) is the total number of lights in a triangular lighting rig of n rows, as shown. Which polynomial function represents T (n + 1) ?

T (n) = 1/2n^2+1/2n

a. T (n+1) = 1/2n^2+3/2n+1

b. T (n+1) = 1/2n^2+1/2n+1

c. T (n+1) = 1/2n^2+n+1

d. T (n+1) = 1/2n^2+1

Question

Mathematics

Laylah Hansen

18 October, 00:03

T (n) is the total number of lights in a triangular lighting rig of n rows, as shown. Which polynomial function represents T (n + 1) ?

T (n) = 1/2n^2+1/2n

a. T (n+1) = 1/2n^2+3/2n+1

b. T (n+1) = 1/2n^2+1/2n+1

c. T (n+1) = 1/2n^2+n+1

d. T (n+1) = 1/2n^2+1

+2

Answers (1)

Know the Answer?

Jewel Bridges · Answer 1

The answer is a. T (n+1) = 1/2n^2+3/2n+1

T (n) = 1/2n² + 1/2n = 1/2 (n² + n)

T (n + 1) = 1/2 ((n+1) ² + (n+1))

(a + b) ² = a² + 2ab + b²

(n + 1) ² = n² + 2n + 1

T (n + 1) = 1/2 (n² + 2n + 1 + n + 1) =

= 1/2 (n² + 3n + 2) =

= 1/2n² + 3/2n + 1

T (n) is the total number of lights in a triangular lighting rig of n rows, as shown. Which polynomial function represents T (n + 1) ?T (n) = 1/2n^2+1/2na. T (n+1) = 1/2n^2+3/2n+1b. T (n+1) = 1/2n^2+1/2n+1c. T (n+1) = 1/2n^2+n+1d. T (n+1) = 1/2n^2+1

T (n) is the total number of lights in a triangular lighting rig of n rows, as shown. Which polynomial function represents T (n + 1) ?

T (n) = 1/2n^2+1/2n

a. T (n+1) = 1/2n^2+3/2n+1

b. T (n+1) = 1/2n^2+1/2n+1

c. T (n+1) = 1/2n^2+n+1

d. T (n+1) = 1/2n^2+1