A 755 N diver drops from a board 10.0 m above the water's surface. Find

the diver's speed 5.00 m above the water's surface. Then find the diver's

speed just before striking the water.

F = 755N, and h = 10.0 m and a = 9.8 m/s^2 and m = ? and v = ? To find the mass use F = ma 755 = (m) (9.8) and m =.77 kg then use the formula KE + PE = PE2 + KE2 which is 1/2mv2 + mgh = mgh (2) + 1/2mv2 (2) to solve for the velocity. v1 = 0 and h1 = 10 and v2 = ? and h2 = 0 (1/2) (.77) (0^2) + (.77) (9.8.) (10) = (1/2) (.77) (V2^2) + (.77) (9.8) (0) v=14 m/s