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14 April, 23:17

Solve "cos 3x = - 1" algebraically given the domain [0,2pi)

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  1. 15 April, 00:33
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    Cos 3 x = - 1, given the domain [ 0, 2 π ].

    3 x = π, x 1 = π / 3 (or : x 1 = 60°)

    3 x = 3 π, x 2 = π (x 2 = 180°)

    3 x = 5 π, x 3 = 5 π / 3 (x 3 = 300°).
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