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Today, 19:33

Derivative of g (x) = (2ra^ (rx) + n) ^p?

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  1. Today, 22:25
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    The main formula of derivative

    if g (x) = a^x, so g' (x) = a^x. lna, a>0, a # 1,

    so g ' (x) = [ (2ra^ (rx) + n) ^p] = 2r. a^ (rx) + n) ^p. ln a

    so g ' (x) = 2r. ln a. a^ (rx) + n) ^p
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