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5 November, 08:56

Find the zeros of the function. f (x) = 6x3 + 18x2 + 12x

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  1. 5 November, 09:14
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    Hello,

    f (x) = 6x^3+18x²+12x=6x (x²+3x+2)

    =6x (x²+x+2x+2) = 6x ((x (x+1) + 2 (x+1))

    =6x (x+1) (x+2)

    Zeros are 0,-1,-2
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