The product of some negative number and 13 less than three times that number is 10. Find the number.

The equation would look like this:

3y - (y*13) = 10

To solve this, we need to be able to get y by itself.

First, put together the 13 and y in the parentheses.

3y - (y*13) = 10

3y - 13y = 10

Next, subtract the 13y from the 3y

3y - 13y = 10

-10y = 10

Finally, divide by - 10 to find what y is equal to.

-10y = 10

-10y : - 10 = 10 : - 10

y = - 1

The number you are looking for is - 1