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6 September, 10:34

What's the axis of symmetry for y=-3x^2+1

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  1. 6 September, 12:51
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    y = - 3x^2 + 1 is a quadratic with a = - 3, b = 0 and c = 1.

    The equation of the axis of symmetry is x = - b / (2a). Here, that comes out to:

    x = 0 / (2*[-3]), or x = 0 (answer)
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