jeff has $,4.05 made up of nickles and dimes. if he has seven times as many nickles as dimes, how many dimes does he have?

Given

jeff has $,4.05 made up of nickles and dimes

he has seven times as many nickles as dimes

Find out the dimes does he have.

To proof

Let us assume that the number of dimes = x

number of nickel = 7x

$,4.05 made up of nickles and dimes.

1 dimes = 0.10$

1 nickel = 0.05$

Than the equation is become in the form

0.10 x + 0.05 (7x) = 4.05

0.10x + 0.35x = 4.05

0.45x = 4.05

x = 9

the number of dimes = 9

number of nickel = 7 * 9

= 63

Hence proved