After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t

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Mathematics

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After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t

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Answers (1)

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Reyna Key · Answer 1

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Step-by-step explanation:

We get 0.811 as our depreciating value because we take 18.9% and turn it into a decimal. Then, we subtract that from 1. If we did 0.189 instead, it would depreciate at a rate of 81.1% annually.

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.Which function describes the value of the car after t years?1) C (t) = 28,000 (0.158) ^t2) C (t) = 28,000 (0.811) ^t3) C (t) = 28.000 (1.575) ^t4) C (t) = 28.000 (0.189) ^t

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

1) C (t) = 28,000 (0.158) ^t

2) C (t) = 28,000 (0.811) ^t

3) C (t) = 28.000 (1.575) ^t

4) C (t) = 28.000 (0.189) ^t