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15 October, 09:17

Let $s$ be the set of all numbers of the form $abc$ where $ (a, b, c) $ is a pythagorean triple. find the gcd of all elements of $s$.

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  1. 15 October, 11:28
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    S = {a, b, c}

    Here a, b, c are Pythagorean triplets.

    Let us first take the smallest triplet 3,4,5

    Now as 3 is a prime number, GCD shall be 1

    Another one is 5, 12, 13.

    Here 13 is a prime number, so GCD shall be 1

    Next one is 20,21, 29

    Here 29 is a prime number, so GCD = 1

    For 15, 8, 17

    17 is a prime number so GCD = 1

    Now when none of them is a prime number'

    For 77,36, 85

    77 = 7 * 11

    36 = 2 * 2 * 3 * 3

    85 = 5 * 17

    Here also the GCD is 1

    So For S = {a, b, c} the Pythagorean triplets the GCD is always 1.
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