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28 April, 19:46

What are the zeros of the quadratic function F (x) = 6x^2+12x-7

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Answers (2)
  1. 28 April, 20:26
    0
    x = - 1 + sqrt (78) / 6

    x = - 1 - sqrt (78) / 6

    Step-by-step explanation:

    Zeros are the x-values where the function is 0

    f (x) = 0

    6x² + 12x - 7 = 0

    a = 6, b = 12, c = - 7

    Using Quadratic formula:

    x = [-12 + - sqrt (12² - 4 (6) (-7) ]/2 (6)

    x = [-12 + - sqrt (312) ]/12

    x = [-12 + 2sqrt (78) ]/12

    x = - 1 + - sqrt (78) / 6
  2. 28 April, 21:35
    0
    x = - 1 + sqrt (78) / 6

    x = - 1 - sqrt (78) / 6
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