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2 September, 08:25

What is a polynomial function in standard form with zeros 1, 2, - 3, and - 1?

g (x) = x^4+x^3-7x^2-x+6

g (x) = x^4+x^3+7x^2-x+6

g (x) = x^4+x^3-7x^2-x-6

g (x) = x^4-x^3-7x^2-x+6

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  1. 2 September, 09:42
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    Answer: [tex] g (x) = x^4+x^3-7x^2-x+6[/tex]

    Step-by-step explanation:

    Since, According to the question,

    1, 2, - 3 and - 1 are zeros of the function g (x),

    Also, function has the degree 4.

    Thus, [tex]g (x) = (x-1) (x-2) (x+3) (x+1) [/tex]

    [tex] g (x) = (x-1) (x-2) (x^2+4x+3) [/tex]

    [tex] g (x) = (x-1) (x^3+4x^2+3x-2x^2-8x-6) [/tex]

    [tex] g (x) = (x-1) (x^3+2x^2-5x-6) [/tex]

    [tex] g (x) = x^4+x^3-7x^2-x+6[/tex]
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