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29 February, 04:10

daniel made a bench that has a seat with an area of 16 square ft the length and the width of the seat are whole numbers the length is 4 times greater than the width what are the dimensions of the seat select the length and width A. 2 ft B. 4 ft C. 6 ft D. 8 ft E. 16 ft

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  1. 29 February, 04:21
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    Answer: The width is option (A) 2 ft and the length is option (D) 8 ft

    Step-by-step explanation: The bench has been constructed and we have been given the area as 16. So we already know that

    Area = L x W

    16 = L x W

    Also we have been given that the length is 4 times greater than the width. This means if the width is W, then the length would be 4 time W, which is 4W.

    Therefore, having known the area as 16 square feet, the equation becomes;

    16 = 4W x W

    16 = 4W²

    We add the square root sign to both sides of the equation and we have

    √16 = √4W²

    4 = 2W

    Divide both sides of the equation by 2,

    2 = W

    With the width now known as 2 ft, the length which had been determined as 4W now becomes

    Length = 4 (2)

    Length = 8

    Therefore, the length is 8 ft, and the width is 2 ft.
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