Given P (A) = 0.33, P (B) = 0.6 and P (A∩B) = 0.248, find the value of P (A∪B), rounding to the nearest thousandth.

The value of P (A ∪ B) is 0.682 to the nearest thousandth

Step-by-step explanation:

The addition rule of probability is:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B), where P (A ∪ B) is probability A or B, P (A ∩ B) is probability A and B

∵ P (A) = 0.33

∵ P (B) = 0.6

∵ P (A ∩ B) = 0.248

- Substitute these values in the rule above

∴ P (A ∪ B) = 0.33 + 0.6 - 0.248

∴ P (A ∪ B) = 0.682

The value of P (A ∪ B) is 0.682 to the nearest thousandth