Ask Question
1 August, 19:19

Have one solution, no solution, or infinitely many solutions

2 (x - 3) = 2x

3 (y - 3) = 2y - 9 + y

10x - 2 - 6x = 3x - 2 + x

4 (x + 3) + 2x = x - 8

+5
Answers (1)
  1. 1 August, 22:29
    0
    2 (x - 3) = 2x

    Cancel 2 on both sides

    x - 3 = x

    Cancel x on both sides

    -3 = 0

    Since - 3 = 0 is false, there is no solution.

    3 (y - 3) = 2y - 9 + y

    Simplify 2y - 9 + y to 3y - 9

    3 (y - 3) = 3y - 9

    Expand

    3y - 9 = 3y - 9

    Since both sides equal, there are infinitely many solutions.

    10x - 2 - 6x = 3x - 2 + x

    Cancel - 2 on both sides

    10x - 6x = 3x + x

    Simplify 10x - 6x to 4x

    4x = 3x + x

    Simplify 3x + x to 4x

    4x = 4x

    Since both sides equal, there are infinitely many solutions.

    4 (x + 3) + 2x = x - 8

    Expand

    4x + 12 + 2x = x - 8

    Simplify 4x + 12 + 2x to 6x + 12

    6x + 12 = x - 8

    Subtract x from both sides

    6x + 12 - x = - 8

    Simplify 6x + 12 - x to 5x + 12

    5x + 12 = - 8

    Subtract 12 from both sides

    5x = - 8 - 12

    Simplify - 8 - 12 to - 20

    5x = - 20

    Divide both sides by 5

    x = - 20/5

    Simplify 20/5 to 4

    x = - 4

    One solution
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Have one solution, no solution, or infinitely many solutions 2 (x - 3) = 2x 3 (y - 3) = 2y - 9 + y 10x - 2 - 6x = 3x - 2 + x 4 (x + 3) + 2x ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers