If y varies jointly as x and z and y = 60 when x = 3 and z = 4, find y when x is 6 and z is 8.

Can aanyone walk me through how to do this?

if y varies jointly with x & z

then y = kxz k = constant > you need to find the constant

first before you can solve this kind of problem

60 = k3*4 y = 60 when x is 3 & z is 4

12k = 60

k = 5

Thus y = 5*6*8 when x = 6 & z = 8

y = 240