A restaurant manager can spend at most 400 a day for operating costs and payroll. It costs $80 each day to operate the restaurant and $40 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day at most

40x+80<400

A x>8

B. x>12

C. x<8

D.<12

C. x<8

Step-by-step explanation:

The restaurant manager can spend at most 400 a day for operating costs and payroll.

Operating cost = $80

Per employee cost = $40

Let the number of employees be x.

Then, total employee cost per day = 40 * x

As per the given requirement,

Fixed operating cost + total daily employee cost < 400

Or, 80 + 40x < 400

Simplifying the inequality:

=> 40x < 400 - 80

=> 40x < 320

=> x < 320/40

=> x < 8

the answer is c

Step-by-step explanation:

40x + 80 < 400

40x < 320

x < 8