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19 May, 01:40

a man travels from town X to town Y at an average rate of 50 miles an hour and returns at an average rate of 40 miles an hour he takes a half hour longer than he would take if he made round trip at an average 45 miles an hour what is the distance from town X to town y

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  1. 19 May, 04:13
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    18 + 22.5 = 40 +.5; confirms out solution

    Step-by-step explanation:

    A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rate of 40 mph. He takes a 1/2 hour longer than he would take if he made the round trip at an average of 45 mph. What is the distance from Town X to Town Y

    :

    Let d = distance from x to y

    :

    Write a time equation; time = distance%2Fspeed

    Different speed roundtrip time = 1 speed roundtrip time + half/hour

    d%2F50 + d%2F40 = 2d%2F45 + 1%2F2

    Multiply equation by 1800 to get rid of the denominators:

    1800*d%2F50 + 1800*d%2F40 = 1800*2d%2F45 + 1800*1%2F2

    Cancel the denominators and you have:

    :

    36d + 45d = 40 (2d) + 900

    :

    81d = 80d + 900

    :

    81d - 80d = 900

    :

    d = 900 miles from x to y

    :

    :

    Check solution in: d%2F50 + d%2F40 = 2d%2F45 + 1%2F2

    900%2F50 + 900%2F40 = 1800%2F45 + 1%2F2

    18 + 22.5 = 40 +.5; confirms out solution
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