An egg is dropped from a height of 90 ft. If acceleration die to gravity is - 16ft/s^2 and initial velocity is 0ft/s, approximately how long will it take for the egg to reach the ground?

t = time

Multiply the acceleration by time and add to the height:

The equation becomes H (t) = - 16 * t^2 + 90

set h (t) to 0

0 = - 16*t^ + 90

Subtract 90 from both sides:

-90 = - 16*t^2

divide both sides by - 16:

t^2 = - 90 / - 16

t^2 = 5.625

t = √5.625

t = 2.37 seconds, round to 2.4 seconds.