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27 November, 17:34

Why is it remarkable that with real coefficients, there must be complex solutions?

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  1. 27 November, 18:59
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    it is important to learn about complex solution because polynomial equation formed over a complex number can only be solved by a complex number.

    this is so because, the fundamental theorem of algebra state that every polynomial equation in one variable with complex coefficient has at least one complex solution.

    Step-by-step explanation:

    it is important to learn about complex solution because polynomial equation formed over a complex number can only be solved by a complex number.

    this is so because, the fundamental theorem of algebra state that every polynomial equation in one variable with complex coefficient has at least one complex solution.

    for example:

    Given any positive integer n ≥ 1 and any choice of complex numbers a0, a1, ..., an, such that an 6 = 0,

    the polynomial equation

    anzn + ··· + a1z + a0 = 0 (1) has at least one solution z ∈C.

    No analogous result holds for guaranteeing that a real solution exists to Equation (1) if we restrict the coefficients a0, a1, ..., an to be real numbers.

    E. g., there does not exist a real number x satisfying an equation as simple as x2 + 1 = 0. Similarly, the consideration of polynomial equations having integer (resp. rational) coefficients quickly forces us to consider solutions that cannot possibly be integers (resp. rational numbers).
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