What is the range of the function f (x) = 3x^2+6-8

The range is all numbers greater than or equal to - 11

Step-by-step explanation:

To find the range, we first need to find the vertex. We can find the x value by using - b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-6/2 (3)

-6/6

-1

So the x value is - 1 and we can find the y value by plugging that in.

f (x) = 3x^2 + 6x - 8

f (-1) = 3 (-1) ^2 + 6 (-1) - 8

f (-1) = 3 (1) - 6 - 8

f (-1) = 3 - 6 - 8

f (-1) = - 11

And since it is a positive equation, we know that this is a minimum.