What is the axis of symetry given f (x) = x^2+4x-19

x = - 2

Step-by-step explanation:

The formula for the axis of symmetry is;

x = - b/2a

In this case;

b = 4, a = 1

Therefore;

x = - 4/2 (1)

= - 2

Thus; the axis of symmetry is x = - 2

x = - 2 is the axis of symmetry.

Step-by-step explanation:

We have given the function:

f (x) = x²+4x-19

We have to find the axis of symmetry.

We know that the formula for axis of symmetry is:

x = - b / 2a

In this equation, b = 4, a = 1

Putting these values we get,

x = - 4/2 (1)

x = - 4/2

x = - 2

x = - 2 is the axis of symmetry of this function.