At t=0, a rock is dropped from rest from the top of a building 256 ft high. With what velocity will it strike the ground? What is it acceleration

128 ft / second.

Step-by-step explanation:

It's acceleration is due to gravity and is 32 ft s^-2.

To find the velocity when it hits the ground we use the equation of motion

v^2 = u^2 + 2gs where u = initial velocity, g = acceleration, s = distance.

v^2 = 0^2 + 2 * 32 * 256

v^2 = 16384

v = 128 ft s^-1.