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6 February, 07:56

Andre and scott share the driving on a trip. Scott drives 7 miles more than three times tge distance Andre drives. If the trip is 111 miles, what distance did scott drive?

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Answers (2)
  1. 6 February, 09:52
    0
    Scott drove 89.5 miles.

    Step-by-step explanation:

    Represent Andre's distance by a and Scott's by s. Then s = 3a + 7.

    Then the total distance driven by both is a + 3a + 7 = 117 (miles), or

    4a - 110 miles, or a = 27.5 miles. Thus, s = 3 (27.5) + 7 = 89.5 miles.
  2. 6 February, 10:28
    0
    Step-by-step explanation:

    What we know is that A + S = 111. That is, the miles Andre drove plus the miles Scott drove totalled 111 miles. What we also know is that Scott drove quite a bit more than Andre did. Scott drove 7 miles more that (+7) 3 times the number of miles Andrea drove. That looks like this algebraically:

    S = 3A + 7

    Now we can sub in that value for S to the original equation:

    If A + S = 111 and S = 3A + 7, then

    A + 3A + 7 = 111 and

    4A + 7 = 111 and

    4A = 104 so

    A = 26 and

    S = 3 (26) + 7 so

    S = 85 miles.

    Scott drove 85 miles.
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