Find the values of a and b such that x^2+2x-7 = (x+a) ^2+b

a = 1, b = - 8

Step-by-step explanation:

you need complete the square to get a and b:

x^2+2x (+1) - 7 (-1)

by adding and subtracting 1 you aren't changing the equation because 1-1=0

then u could simplify the equation to

(x+1) ^2 - 8 to get a=1 and b=-8