If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

Answer: 5,499,187,200

Step-by-step explanation:

A coin is tossed 5 times.

There are two options (heads or tails) so the possible outcomes are: 2⁵

A six-sided die is rolled 4 times.

There are six options so the possible outcomes are: 6⁴

A group of 3 cards are drawn (without replacement).

The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50

Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:

2⁵ x 6⁴ x 52 x 51 x 50

= 32 x 1296 x 132,600

= 5,499,187,200

Answer: 916531200 or

9.165132 x 10^8

Step-by-step explanation:

If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally, a group of three cards is drawn from a standard deck of 52 cards without replacements, how many different outcomes are possible?

a coin is tossed 5 times,

outcomes: 2^5 = 32

and then a standard six-sided die is rolled 4 times,

outcomes: 6^4 = 1296

and finally, a group of three cards is drawn from a standard deck of 52 cards without replacements

It says a "group", so, I guess the order doesn't matter ... So it is "52 choose 3"

52*51*50 / (3*2*1) = 52*17*25

how many different outcomes are possible?

32*1296*52*17*25 = 916531200