The ages of three siblings total 32 years. The middle child is 4 years older than the youngest, and the eldest is twice as old as the youngest. How old is each child?

x = 7

y = 11

z = 14

Step-by-step explanation:

x + y + z = 32

Let's say the youngest is x, middle is y and oldest is z.

y = x+4 (age of the youngest + 4)

z = 2x (twice as old)

We can replace y and z in the main equation above with these values that contain x.

x + (x + 4) + 2x = 32

4x = 28, divide both sides by 4

x = 7

y = x + 4 = 7 + 4 = 11

z = 2x = 2*7 = 14

And to check: 7 + 11 + 14 = 32

Oldest=14

Middle=11

Youngest=7

Step-by-step explanation:

Oldest is 2x youngest (7*2=14)

one you figure out the youngest (7) then * 2 to get eldest (14)

32-7=25

25-14=11<--age of middle child that is 4 years older than youngest (7+4=11)