Which of the following are roots of the polynomial function?

F (x) = x^3-x^2-5x-3

Answer with explanation:

The given Polynomial function is:

F (x) = x³-x²-5 x - 3

By Rational root theorem, roots of the polynomial can be 1,-1, 3,-3.

F (3) = 3³-3²-5*3-3

=27-9-15-3

= 0

So, 3 is one of the root of the equation.

That is, (x-3) will divide the whole polynomial.

F (x) = x³-x²-5 x - 3

= (x-3) (x²+2 x + 1)

= (x-3) (x+1) ²

to get the roots.

1. x-3=0

⇒x=3

2. (x+1) ²=0

⇒x+1=0

⇒x = - 1

So, root of the polynomial function are=3, and,-1.

Option B=3 and Option C = - 1

Try this option:

the function can be re-written in a form f (x) = (x+1) (x+1) (x-3);

The roots of the function are 3 and - 1