Mr. Kaplan bought 11 tickets to the circus and spent $50. He bought child tickets for $4 each and bought adult tickets for $7 each. How many child and adult tickets did Mr. Kaplan buy?

Mr Kaplan bought 9 child tickets and 2 adult tickets.

Step-by-step explanation:

- Mr Kaplan bought 11 tickets

- He spent $50

- Child tickets cost $4 each

- Adult tickets cost $4 each.

We want to know how many adult ticket and child ticket Mr Kaplan bought.

Better still, we want to know exactly how many $4's and $7's make $50.

Let us try out the numbers that sum up to 11.

10 + 1 = 11

9 + 2 = 11

8 + 3 = 11

7 + 4 = 11

6 + 5 = 11

Next, let us check which one (s) of these number when applied to the costs of tickets gives 50

(10*$4) + (1 * $7) = $47 ≠ $50

(10*$7) + (1*$4) = $74 ≠ 50 (10*$7, 9*$7, 8*$7, and 7*$7 are already too much, it is reasonable to ignore them)

Let's try the next one

(9*$4) + (2*$7) = $50 (This works)

Next,

(8*$4) + (3*$7) = $53 ≠ 50

(7*$4) + (4*$7) = $56 ≠ 50

(6*$5) + (5*$7) = $65 ≠ 50

So, we can conclude that Mr Kaplan bought 9 child tickets and 2 adult tickets.