Determine the values of a for which the following system of linear equations has no solutions, a unique solution, or infinitely many solutions. You can select 'always', 'never', 'a = ', or 'a ≠', then specify a value or comma-separated list of values. 2x1-6x2-4x3 = 6 - x1+ax2+4x3 = - 1 2x1-5x2-2x3 = 9

Never

Never

Never

Step-by-step explanation:

The equations given are

2x1-6x2-4x3 = 6 ... (1)

-x1+ax2+4x3 = - 1 ... (2)

2x1-5x2-2x3 = 9 ... (3)

the values of a for which the system of linear equations has no solutions

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.

a unique solution,

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

The value of a = never

infinitely many solutions.

Divide equation 1 by 2 we will get

X1 - 3X2 - 2X3 = 3

Add the above equation with equation 3. This will result to

3X1 - 8X2 - 4X3 = 12

Everything ought to be the same. Since they're not.

Value of a = never.