A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is replaced before the second marble is drawn, what is P (blue second | green first) ?

A. 210

B. 410

C. 510

D. 610

4/10

Step-by-step explanation:

4 blue and 6 green marbles. = 10 marbles

We draw a second marble

P (blue) = blue marbles / total marbles = 4/10

The first is an independent even since the marble is replaced

P (blue second given a green first) = 4/10