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28 October, 10:42

Write the given second order equation as its equivalent system of first order equations. u″+5u′+4u=0 u″+5u′+4u=0 use vv to represent the "velocity function", i. e. v=u′ (t) v=u′ (t). use vv and uu for the two functions, rather than u (t) u (t) and v (t) v (t).

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  1. 28 October, 11:35
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    v = u', so v' = u'' and the original equation can be written

    ... v' + 5v + 4u = 0

    Then the system of first-order equations is

    ... u' = v

    ... v' = - 5v - 4u
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