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6 January, 04:09

An architectural engineer is designing a parabola dome that will be 200 feet in diameter with a max height of 50 feet. find the equation for the cross sectional parabola of the dome. y = what?

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  1. 6 January, 06:38
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    y = - 0.005x² + 50

    Step-by-step explanation:

    The diameter is 200 feet, so the parabola has roots at (-100, 0) and (100, 0). The maximum height is 50, so the vertex of the parabola is at (0, 50).

    Using vertex form of a parabola:

    y = a (x - h) ² + k

    y = a (x - 0) ² + 50

    y = ax² + 50

    Plugging in either root:

    0 = a (100) ² + 50

    a = - 0.005

    y = - 0.005x² + 50
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