What are the five other terms in the sequence if t (1) = - 3 and t (n+1) = - 2t (n) ?

Put n = - 1 on both side

t (0) = - 2t (-1)

Now put n=0

We get t (1) = - 2t (0)

t (0) = 3/2

t (1) = - 2*3/2=-3

Put n=1

T (2) = - 2*t (1)

-2*-3

6

Now you can easily found

T (n+1) = - 2t (n)

t (n+1) is the term after t (n)

so each term is found by multipilying the prvious term by - 2

so

first term is - 3

2nd is 6

3rd is - 12

4th is 24

5th is - 48

6th is 96

7th is - 192

thos are some terms