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1 May, 07:08

Two numbers that have a sum of 100 and a diffrence of 6

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Answers (2)
  1. 1 May, 09:09
    0
    50 + 50 = 100 bus the difference is 0

    (50 + 3) + (50 - 3) = 100 and the difference is 6

    53 and 47 are the numbers

    other way

    I. x + y = 100

    II. x - y = 6

    I + II 2x = 106 - -> x = 53

    53 + y = 100 - -> y = 47
  2. 1 May, 10:15
    0
    x and y are the two numbers, which are unknown for now. Their sum is 100, so x+y = 100. Their difference is 6, so x-y = 6 (assume x is the larger value)

    The system of equations we have is

    x+y = 100

    x-y = 6

    Add the equations straight down. The x terms combine to x+x = 2x. The y terms cancel out because y + (-y) = y-y = 0y = 0. The right hand sides combine to 100+6 = 106

    So we end up with 2x = 106. Divide both sides by 2 to get x = 53.

    If x = 53, then ...

    x+y = 100

    53+y = 100

    y = 100-53

    y = 47

    Final Answer: The two numbers are 53 and 47

    Check:

    53 + 47 = 100

    53 - 47 = 6
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