Hiyaa there; )

A circular hot spring has a diameter of 110 meters. Over time, the diameter

of the spring decreases by 3 meters. By how many square meters does the

area of the hot spring decrease?

(answer quick)

Originally, the diameter was 110 m, so the radius was 55 m. To get the area, you square the radius and multiply by π. That's 55^2 * π, making the original area 3025π m^2.

After, the diameter decreased to 107 m, making the radius 53.5 m. Again, you square the radius and multiply by π, making the new area 2862.25π m^2.

Subtract the 2862.25π from 3025π, giving you a total reduction of 162.75π square meters.

Rounded to the nearest hundredth, that's 511.29 square meters.