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16 March, 04:22

A sample of 3 different bulbs is randomly selected from a group containing 8 that are defective and 22 that have no defects. What is the probability that at least one of the bulbs is defective? Round answer to three decimal places.

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  1. 16 March, 05:31
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    Probability of drawing non defective bulb

    =90/100*89/99*88/98 * ... * 82/92 ... (i) = 90/100*89/99*88/98 * ... * 82/92 ... (i)

    Now the probability of drawing at least one bulb will be defective

    =1 - (i) = 1-90/100*89/99*88/98 * ... * 82/92

    1 - (90/100⋅89/99⋅ ...⋅83/93)
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