Solve 3^ (4x-5) = 〖27〗^ (x+10) for x. Show your work

x = 35

Step-by-step explanation:

27 = 3^3

so now it would be (3^3) ^x+10, you multiply the exponents and get 3^3x+30

so now you have two bases that have a 3, by rule, if you have the same bases your exponents should be the same, so you just equal the other exponent which is 4x-5

so 4x - 5 = 3x + 30

4x - 3x = 30 + 5

x = 35