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27 November, 12:08

Find two consecutive odd integers such that three times the larger is 5 less than four times the smaller

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  1. 27 November, 14:57
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    Let n=smallest number

    Let n+2=largest number

    3 (n+2) = 4 (n) - 5

    3n+6=4n-5

    -n=-11

    n=11

    11+2=13

    The smallest number is 11 and the largest number is 13
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