The length of one side of a triangular lot is 6 m less than 3 times the length of the second side. The third side is 8 m longer than the first side. The perimeter of the lot is 80 m. Find the length of all three sides.

second side = x

first side = 3x - 6

third side = (3x - 6) + 8

The perimeter = 80m and is equal x + (3x - 6) + [ (3x - 6) + 8]

x + 3x - 6 + 3x - 6 + 8 = 80

7x - 4 = 80 |+4

7x = 84 |:7

x = 12 m

3x - 6 = 3 (12) - 6 = 30 m

(3x - 6) + 8 = 3x + 2 = 3 (12) + 2 = 38 m

Answer: 12m, 30m, 38m