There are three consecutive even numbers such that twice the first is 20 more than the second. Find the number

22, 24, 26

Step-by-step explanation:

2n is an even number.

Your three even numbers are 2n, 2n + 2, 2n + 4

Twice the first is 20 more than the second.

2n * 2 = 2n + 2 + 20

Simplify:

4n = 2n + 22

Use simultaneous equations to solve n.

4n = 2n + 22 - 2n

2n = 22 : 2

n = 11

Subsitiye n into the three even numbers.

2n, 2n + 2, 2n + 4

2 * 11, 2 * 11 + 2, 2 * 11 + 4

22, 24, 26

Check that the numbers meet the requirements.

22 * 2 = 24 + 20

44 = 44