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Today, 16:28

If x = 1 is a zero of the polynomial x3 - 7x + 6, find the other two zeroes.

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  1. Today, 18:47
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    x = - 3, x = 2

    Step-by-step explanation:

    Since x = 1 is a zero then (x - 1) is a factor of the polynomial

    dividing x³ - 7x + 6 : (x - 1)

    = (x - 1) (x² + x - 6)

    = (x - 1) (x + 3) (x - 2)

    equating (x + 3) (x - 2) = 0 gives the other zeros

    equate each factor to zero and solve for x

    x + 3 = 0 ⇒ x = - 3

    x - 2 = 0 ⇒ x = 2
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