Write an equation to represent the following: Three consecutive integers add up to 11 more than the smallest.

Step-by-step explanation:

First we have to assume the smallest integer.

Let,

the smallest integer is x

So, the other two integers are-

x+1 and x+2

Now,

the sum of these 3 integers is greater than smallest integer by 11

So, we get

x + (x+1) + (x+2) = x+11

This is the required equation.