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16 June, 17:46

The area of a rectangle invitation card is 3/10 square foot. Given that the length of the card is 4/5 foot, find its perimeter.

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  1. 16 June, 20:11
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    Area is length times width [A = (L) (W) ], if we know that the area of the card is 3/10 and the length is 4/5 we can set up the equation 3/10 = (4/5) (W) where W is width. Solve for W by deciding both sides by 4/5 and we get that W=3/8. To find the perimeter of the card were have to add up all the sides of the card so 3/8+3/8+4/5+4/5 which equals 47/20
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