Ask Question
22 July, 12:46

Anya and Jake started new jobs at the same time. Anya's starting salary was $42,000, and she gets a $1,500 raise each year. Jake's starting salary was $35,000, and he gets a 3% raise each year.

+1
Answers (1)
  1. 22 July, 14:21
    0
    J (x) = 1050x+35000

    Step-by-step explanation:

    The complete question is

    Anya and Jake started new jobs at the same time. Anya's starting salary was $42,000, and she gets a $1,500 raise each year. Jake's starting salary was $35,000, and he gets a 3% raise each year. What function gives Jake's salary after x years?

    Solution

    The starting salary refers to the initial condition, the salary Jake began from. That means, it's the constant term in the function.

    On the other hand, the constant ratio of change of the function is the yearly raise, which is 3% of $35,000. Let's find how much money it is.

    0.03 (35000) = 1050

    This means, they raise Jake's salary $1,050 each year, that's the constant ratio of change.

    Therefore, the function which represents Jake's salary is

    J (x) = 1050x+35000

    Where x represents years.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Anya and Jake started new jobs at the same time. Anya's starting salary was $42,000, and she gets a $1,500 raise each year. Jake's starting ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers