Anya and Jake started new jobs at the same time. Anya's starting salary was $42,000, and she gets a $1,500 raise each year. Jake's starting salary was $35,000, and he gets a 3% raise each year.

J (x) = 1050x+35000

Step-by-step explanation:

The complete question is

Anya and Jake started new jobs at the same time. Anya's starting salary was $42,000, and she gets a $1,500 raise each year. Jake's starting salary was $35,000, and he gets a 3% raise each year. What function gives Jake's salary after x years?

Solution

The starting salary refers to the initial condition, the salary Jake began from. That means, it's the constant term in the function.

On the other hand, the constant ratio of change of the function is the yearly raise, which is 3% of $35,000. Let's find how much money it is.

0.03 (35000) = 1050

This means, they raise Jake's salary $1,050 each year, that's the constant ratio of change.

Therefore, the function which represents Jake's salary is

J (x) = 1050x+35000

Where x represents years.