Ask Question
25 July, 13:38

Use technology or a z-score table to answer the question.

The number of baby carrots in a bag is normally distributed with a mean of 94 carrots and a standard deviation of 8.2 carrots.

Approximately what percent of the bags of baby carrots have between 90 and 100 carrots?

+1
Answers (1)
  1. 25 July, 16:40
    0
    Answer: 46%

    Step-by-step explanation:

    Since the number of baby carrots in a bag is normally distributed, we would apply the formula for normal distribution which is expressed as

    z = (x - µ) / σ

    Where

    x = the number of baby carrots in the bag.

    µ = mean

    σ = standard deviation

    From the information given,

    µ = 94 carrots

    σ = 8.2 carrots

    The probability that a bag of baby carrots have between 90 and 100 carrots is expressed as

    P (90 ≤ x ≤ 100)

    For x = 90,

    z = (90 - 94) / 8.2 = - 0.49

    Looking at the normal distribution table, the probability corresponding to the z score is 0.31

    For x = 100,

    z = (100 - 94) / 8.2 = 0.73

    Looking at the normal distribution table, the probability corresponding to the z score is 0.77

    Therefore,

    P (90 ≤ x ≤ 100) = 0.77 - 0.31 = 0.46

    The percent of the bags of baby carrots that have between 90 and 100 carrots is

    0.46 * 100 = 46%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Use technology or a z-score table to answer the question. The number of baby carrots in a bag is normally distributed with a mean of 94 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers