The weights of packages of crackers are normally distributed with a mean of 340 grams and a standard deviation of 12 grams.

What is the weight of a package of crackers with a z-score of - 1.4?

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Answer: the weight of the package of crackers is 323.2 grams

Step-by-step explanation:

Since the weights of packages of crackers are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ) / σ

Where

x = weights of packages of crackers.

µ = mean weight

σ = standard deviation

From the information given,

µ = 340 grams

σ = 12 grams

The z score of the package is - 1.4

Therefore,

- 1.4 = (x - 340) / 12

Cross multiplying by 12, it becomes

- 1.4 * 12 = x - 340

- 16.8 = x - 340

x = - 16.8 + 340

x = 323.2 grams