Consider the function ƒ (x) = 3x2 + 6x + 5.

Write the function in the form of ƒ (x) = a (x - h) 2 + k, where a, h and k are constants.

f (x) = 3 (x + 1) ² + 2

Step-by-step explanation:

Use the method of completing the square

3x² + 6x + 5

= 3 (x² + 2x) + 5

add / subtract (half the coefficient of the x-term) ² to x² + 2x

= 3 (x² + 2 (1) x + 1 - 1) + 5

= 3 (x + 1) ² - 3 + 5

f (x) = 3 (x + 1) ² + 2 ← in vertex form